![tanA / 1-CotA + CotA / 1-TanA = 1 + TanA + Cot A - Maths - Introduction to Trigonometry - 1192102 | Meritnation.com tanA / 1-CotA + CotA / 1-TanA = 1 + TanA + Cot A - Maths - Introduction to Trigonometry - 1192102 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/userimages/mn_images/image/a1(1355).png)
tanA / 1-CotA + CotA / 1-TanA = 1 + TanA + Cot A - Maths - Introduction to Trigonometry - 1192102 | Meritnation.com
With steps prove that (TanA/1-cotA)+(cotA/1-tanA)=1+tanA+cotA Introduction to Trigonometry-Maths-Class-10
Prove: tanA/(1-cotA) + cotA/(1-tanA) = secAcosecA + 1 - Sarthaks eConnect | Largest Online Education Community
Prove that tanA/(1-cotA) + cotA/(1-tanA) = (1+tanA + cotA) - Sarthaks eConnect | Largest Online Education Community
![The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s e c A""cos e c A""+""1 (2) t a n A""+""cot A (3) s e c A""+""cos e c A (4) s in A""cos A""+""1 The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s e c A""cos e c A""+""1 (2) t a n A""+""cot A (3) s e c A""+""cos e c A (4) s in A""cos A""+""1](https://d10lpgp6xz60nq.cloudfront.net/ss/web/10682.jpg)
The expression (tanA)/(1-cotA)+(cotA)/(1-tanA) can be written as (1) s e c A""cos e c A""+""1 (2) t a n A""+""cot A (3) s e c A""+""cos e c A (4) s in A""cos A""+""1
![tanA/(1-cotA)+cotA/(1-tanA)=1+tanA+cotA=1+secAcosecA` `(1 +costheta+sintheta)/(1+costheta-sint... - YouTube tanA/(1-cotA)+cotA/(1-tanA)=1+tanA+cotA=1+secAcosecA` `(1 +costheta+sintheta)/(1+costheta-sint... - YouTube](https://i.ytimg.com/vi/8nkz6Uc9S_A/maxresdefault.jpg)